437.Path Sum III

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Question

You are given a binary tree in which each node contains an integer value.

Find the number of paths that sum to a given value.

The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes).

The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000.

Example:

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root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8
      10
     /  \
    5   -3
   / \    \
  3   2   11
 / \   \
3  -2   1
Return 3. The paths that sum to 8 are:
1.  5 -> 3
2.  5 -> 2 -> 1
3. -3 -> 11

Answer

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/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    public int pathSum(TreeNode root, int sum) {
        if(root == null)
            return 0;
        return findPathFromNode(root, sum) + pathSum(root.left, sum) + pathSum(root.right, sum);
    }
    
    public int findPathFromNode(TreeNode root, int sum){
        int cnt = 0;
        if(root == null)
            return cnt;
        if(root.val == sum)
            cnt++;
        cnt += findPathFromNode(root.left, sum-root.val); 
        cnt += findPathFromNode(root.right, sum-root.val);
        return cnt;
    }
}