155.Min Stack

Stack, Easy

Question

Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.

  • push(x) – Push element x onto stack.
  • pop() – Removes the element on top of the stack.
  • top() – Get the top element.
  • getMin() – Retrieve the minimum element in the stack.

Example:

1
2
3
4
5
6
7
8
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); --> Returns -3.
minStack.pop();
minStack.top(); --> Returns 0.
minStack.getMin(); --> Returns -2.

My Answer

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
class MinStack {
Stack<Integer> stack = new Stack<>();
Stack<Integer> min = new Stack<>();
/** initialize your data structure here. */
public MinStack() {
}
public void push(int x) {
if(min.isEmpty() || x<=min.peek())
min.push(x);
stack.push(x);
}
public void pop() {
if(stack.peek().equals(min.peek()))
min.pop();
stack.pop();
}
public int top() {
return stack.peek();
}
public int getMin() {
return min.peek();
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/

Running time: 101ms